3[4b+2(b+3)+2]+5(2+3b)=

Solution for 3[4b+2(b+3)+2]+5(2+3b)= equation:

Simplifying
3[4b + 2(b + 3) + 2] + 5(2 + 3b) = 0

Reorder the terms:
3[4b + 2(3 + b) + 2] + 5(2 + 3b) = 0
3[4b + (3 * 2 + b * 2) + 2] + 5(2 + 3b) = 0
3[4b + (6 + 2b) + 2] + 5(2 + 3b) = 0

Reorder the terms:
3[6 + 2 + 4b + 2b] + 5(2 + 3b) = 0

Combine like terms: 6 + 2 = 8
3[8 + 4b + 2b] + 5(2 + 3b) = 0

Combine like terms: 4b + 2b = 6b
3[8 + 6b] + 5(2 + 3b) = 0
[8 * 3 + 6b * 3] + 5(2 + 3b) = 0
[24 + 18b] + 5(2 + 3b) = 0
24 + 18b + (2 * 5 + 3b * 5) = 0
24 + 18b + (10 + 15b) = 0

Reorder the terms:
24 + 10 + 18b + 15b = 0

Combine like terms: 24 + 10 = 34
34 + 18b + 15b = 0

Combine like terms: 18b + 15b = 33b
34 + 33b = 0

Solving
34 + 33b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-34' to each side of the equation.
34 + -34 + 33b = 0 + -34

Combine like terms: 34 + -34 = 0
0 + 33b = 0 + -34
33b = 0 + -34

Combine like terms: 0 + -34 = -34
33b = -34

Divide each side by '33'.
b = -1.03030303

Simplifying
b = -1.03030303